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причастие
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1. This says the variance of
p
hat sub 1 minus
p
hat sub 2 is equal to, and I’m running
2. the same except for these
p
hats were missing, and Ps, just
p
alone was in its place. Again,
3. between our two sample proportions, so
p
hat sub 1 times (1-
p
hat sub1) over n1 plus
p
4. So now we're done, because this shows
P
n plus 1.
5. sample proportions in this calculation, the standard error of
p
hat sub 1 minus
p
hat
6. We assume that
P
of m holds.
7. We assume that
P
of m holds.
8. So we suppose
P
of n.
9. hat sub 2 is equal to the mean of
p
hat1 plus or minus the mean of
p
hat, of
p
sub 2.
P
10.
p
(1-
p
)/n, the sub 2s because it’s the second group, and I’m squaring that standard deviation
11. population distribution, then we can say that the mu of
p
hat sub 1 minus
p
hat sub 2 is
12. mu of
p
hat equals
p
, since the center of our sampling distribution is the same as the
13. or minus p1 plus or minus
p
hat sub 2 is equal to the mean of
p
hat sub 1 plus or minus
p
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